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Solution to Enigma No. 1526

By Bob Walker

31 December 2008

Read the original question

Answer: The true temperature was 80ºC

The winner is Mike Waterman of Camberley, Surrey, UK. There were 124 entries.

Worked answer

Notation

  • TC = Temperature indicated in ºC
  • TF = Temperature indicated in ºF
  • TT = True temperature in ºC
  • EC = Error Factor – ºC Measurement
  • EF = Error Factor – ºF Measurement

Basic Formulae

  • TC = TT . EC…..(1)
  • TF = (TT . 9/5 + 32). EF…..(2)
  • TT = TC/EC = (TF/EF – 32). 5/9…..(3)

Calculations

  • TC = 76.3
  • TF = 150.1
  • 76.3/EC = (150.1/EF – 32) . 5/9…..(3)
  • TC = 98.1
  • TF = 184.3
  • 98.1/EC = (184.3/EF – 32) . 5/9…..(3)

Eliminating EC

  • 76.3 (184.3/EF – 32) = 98.1 (150.1/EF – 32)
  • EF = 0.95
  • With TF = 167.2
  • &
  • TT = (TF/EF – 32) . 5/9…..(2)
  • TT= (167.2/0.95-32) . 5/9=80

Solution = 80ºC

Read the original question

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